Category: Updates

Polar form of $\frac{1}{z}$

Write the following in polar form:$$\frac{1}{z}$$ $$\frac{1}{z}=\frac{1}{x+yi}$$ $$\frac{1}{x+yi}\cdot \frac{x-yi}{x-yi}=\frac{x-yi}{x^2+y^2}=\frac{x-yi}{...