I need to find the negations of the following statements:
For every n (is an element of natural numbers) there is a prime number p such that n < p.
There is n (is an element of natural numbers) such that for every prime number p, p < n.
What are the rules of negation for these statements? Thanks!
$\endgroup$ 11 Answer
$\begingroup$The negation of $\forall x.P$ is $\exists x .(\neg P)$.
Similarly, we have $\neg (\exists x .P) \equiv \forall x (.\neg P)$.
$\endgroup$