I would like to remove exponentiation in this equation $y=x^t$ and use only multiplication or division. I have $x, t$ and $\ln(x)$. Is it possible?
$\endgroup$ 12 Answers
$\begingroup$$y=x^t$
This gives you: $\ln(y) = \ln(x^t) = t \ln(x)\quad\implies \quad \ln(y) = t \ln(x)$
Here we use the rule of logarithms (which applies to "$\ln$" as well):
$\endgroup$ 3 $\begingroup$$$\log(a^b) = b \log (a)$$
When $a>0$ then we are always allowed to have $$\ln(a^b)=b\ln(a)$$ So take a Neperian logarithm from both sides of your identity.
$\endgroup$ 2