Let $G=\{x\in\mathbb{R}~|~0\le x<1\}$ and define $\star$ as follows
$$x\star y=x+y-[x+y]$$
I want to show this is a well defined operation. I think it is this easy;
If $x=x', y=y'$, then
$$x\star y = x+y-[x+y]=x'+y'-[x'+y']=x'\star y'$$
Is this accurate?
$\endgroup$ 101 Answer
$\begingroup$We have:
$$\lfloor x \rfloor \le x \lt \lfloor x \rfloor + 1$$
so that:
$$0 \le x-\lfloor x \rfloor\lt 1$$
So your function is well defined $$x\star y:G\to G$$
$\endgroup$ 0