For small values of $\theta$, $\sin\theta = \theta$ this must be done in what units radians or degrees
Sin (6°)=6 or sin(6)=6
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$\begingroup$Not even close. sin(6 radians) is nowhere close to 0.
However, sin(6 degrees) = $\sin(\frac{π}{30})=\sin(0.1047)=0.1045$.
Trigonometric functions are naturally in radians.
$\endgroup$ $\begingroup$By Taylor expansion, we have
$$\sin (x)=x+x^2 (1+\epsilon (x)) $$ thus for very small values of $x $ in RADIANS, we can write $$\sin (x)\approx x .$$
but $$x (deg)=180\frac {x (rad)}{\pi}$$ $$\approx 57.2 x(rad)$$
thus the approximation is not correct if $x $ is in degree.
$\endgroup$ $\begingroup$We know that $sin^2(\theta)+cos^2(\theta)=1.$ So $sin^2(\theta) \leq 1.$ So $-1 \leq sin(\theta) \leq 1.$ So neither 6 nor 6º complies what you put. What is true is that $sin(6*(\frac{\pi}{180})) \approx 6*(\frac{\pi}{180})$. For being $6 \leq 15$
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